(X+1)/x=1-(x^2-3x-4)/4x

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Solution for (X+1)/x=1-(x^2-3x-4)/4x equation: 



(X+1)/X=1-(X^2-3X-4)/4X

We move all terms to the left:

(X+1)/X-(1-(X^2-3X-4)/4X)=0



Domain of the equation: X!=0

X∈R





Domain of the equation: 4X)!=0

X!=0/1

X!=0

X∈R



We calculate fractions


(X+1)*4X)/4X^2+(-(1-(X^2-3X-4)*X)/4X^2=0

We calculate fractions


((X+1)*4X)*4X^2)/(4X^2+(*4X^2)+(-(1-(X^2-3X-4)*X)*4X^2)/(4X^2+(*4X^2)=0



We calculate terms in parentheses: +(-(1-(X^2-3X-4)*X)*4X^2)/(4X^2+(*4X^2), so:

-(1-(X^2-3X-4)*X)*4X^2)/(4X^2+(*4X^2

We multiply all the terms by the denominator


-(1-(X^2-3X-4)*X)*4X^2)+((*4X^2)*(4X^2

Back to the equation:

+(-(1-(X^2-3X-4)*X)*4X^2)+((*4X^2)*(4X^2)



We get rid of parentheses

((X+1)*4X)*4X^2)/(4X^2+*4X^2+(-(1-(X^2-3X-4)*X)*4X^2)+((*4X^2)*4X^2=0

We multiply all the terms by the denominator


((X+1)*4X)*4X^2)+(*4X^2)*(4X^2+((-(1-(X^2-3X-4)*X)*4X^2))*(4X^2+(((*4X^2)*4X^2)*(4X^2=0

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